Optimal. Leaf size=781 \[ \frac{10 b x^2 \text{PolyLog}\left (2,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d^2 \sqrt{b^2-a^2}}-\frac{10 b x^2 \text{PolyLog}\left (2,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d^2 \sqrt{b^2-a^2}}+\frac{40 i b x^{3/2} \text{PolyLog}\left (3,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d^3 \sqrt{b^2-a^2}}-\frac{40 i b x^{3/2} \text{PolyLog}\left (3,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d^3 \sqrt{b^2-a^2}}-\frac{120 b x \text{PolyLog}\left (4,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d^4 \sqrt{b^2-a^2}}+\frac{120 b x \text{PolyLog}\left (4,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d^4 \sqrt{b^2-a^2}}-\frac{240 i b \sqrt{x} \text{PolyLog}\left (5,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d^5 \sqrt{b^2-a^2}}+\frac{240 i b \sqrt{x} \text{PolyLog}\left (5,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d^5 \sqrt{b^2-a^2}}+\frac{240 b \text{PolyLog}\left (6,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d^6 \sqrt{b^2-a^2}}-\frac{240 b \text{PolyLog}\left (6,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d^6 \sqrt{b^2-a^2}}+\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d \sqrt{b^2-a^2}}-\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d \sqrt{b^2-a^2}}+\frac{x^3}{3 a} \]
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Rubi [A] time = 1.17976, antiderivative size = 781, normalized size of antiderivative = 1., number of steps used = 19, number of rules used = 9, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.45, Rules used = {4204, 4191, 3321, 2264, 2190, 2531, 6609, 2282, 6589} \[ \frac{10 b x^2 \text{PolyLog}\left (2,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d^2 \sqrt{b^2-a^2}}-\frac{10 b x^2 \text{PolyLog}\left (2,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d^2 \sqrt{b^2-a^2}}+\frac{40 i b x^{3/2} \text{PolyLog}\left (3,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d^3 \sqrt{b^2-a^2}}-\frac{40 i b x^{3/2} \text{PolyLog}\left (3,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d^3 \sqrt{b^2-a^2}}-\frac{120 b x \text{PolyLog}\left (4,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d^4 \sqrt{b^2-a^2}}+\frac{120 b x \text{PolyLog}\left (4,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d^4 \sqrt{b^2-a^2}}-\frac{240 i b \sqrt{x} \text{PolyLog}\left (5,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d^5 \sqrt{b^2-a^2}}+\frac{240 i b \sqrt{x} \text{PolyLog}\left (5,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d^5 \sqrt{b^2-a^2}}+\frac{240 b \text{PolyLog}\left (6,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d^6 \sqrt{b^2-a^2}}-\frac{240 b \text{PolyLog}\left (6,-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d^6 \sqrt{b^2-a^2}}+\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{b^2-a^2}}\right )}{a d \sqrt{b^2-a^2}}-\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{\sqrt{b^2-a^2}+b}\right )}{a d \sqrt{b^2-a^2}}+\frac{x^3}{3 a} \]
Antiderivative was successfully verified.
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Rule 4204
Rule 4191
Rule 3321
Rule 2264
Rule 2190
Rule 2531
Rule 6609
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{x^2}{a+b \sec \left (c+d \sqrt{x}\right )} \, dx &=2 \operatorname{Subst}\left (\int \frac{x^5}{a+b \sec (c+d x)} \, dx,x,\sqrt{x}\right )\\ &=2 \operatorname{Subst}\left (\int \left (\frac{x^5}{a}-\frac{b x^5}{a (b+a \cos (c+d x))}\right ) \, dx,x,\sqrt{x}\right )\\ &=\frac{x^3}{3 a}-\frac{(2 b) \operatorname{Subst}\left (\int \frac{x^5}{b+a \cos (c+d x)} \, dx,x,\sqrt{x}\right )}{a}\\ &=\frac{x^3}{3 a}-\frac{(4 b) \operatorname{Subst}\left (\int \frac{e^{i (c+d x)} x^5}{a+2 b e^{i (c+d x)}+a e^{2 i (c+d x)}} \, dx,x,\sqrt{x}\right )}{a}\\ &=\frac{x^3}{3 a}-\frac{(4 b) \operatorname{Subst}\left (\int \frac{e^{i (c+d x)} x^5}{2 b-2 \sqrt{-a^2+b^2}+2 a e^{i (c+d x)}} \, dx,x,\sqrt{x}\right )}{\sqrt{-a^2+b^2}}+\frac{(4 b) \operatorname{Subst}\left (\int \frac{e^{i (c+d x)} x^5}{2 b+2 \sqrt{-a^2+b^2}+2 a e^{i (c+d x)}} \, dx,x,\sqrt{x}\right )}{\sqrt{-a^2+b^2}}\\ &=\frac{x^3}{3 a}+\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}-\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}-\frac{(10 i b) \operatorname{Subst}\left (\int x^4 \log \left (1+\frac{2 a e^{i (c+d x)}}{2 b-2 \sqrt{-a^2+b^2}}\right ) \, dx,x,\sqrt{x}\right )}{a \sqrt{-a^2+b^2} d}+\frac{(10 i b) \operatorname{Subst}\left (\int x^4 \log \left (1+\frac{2 a e^{i (c+d x)}}{2 b+2 \sqrt{-a^2+b^2}}\right ) \, dx,x,\sqrt{x}\right )}{a \sqrt{-a^2+b^2} d}\\ &=\frac{x^3}{3 a}+\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}-\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}+\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}-\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}-\frac{(40 b) \operatorname{Subst}\left (\int x^3 \text{Li}_2\left (-\frac{2 a e^{i (c+d x)}}{2 b-2 \sqrt{-a^2+b^2}}\right ) \, dx,x,\sqrt{x}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{(40 b) \operatorname{Subst}\left (\int x^3 \text{Li}_2\left (-\frac{2 a e^{i (c+d x)}}{2 b+2 \sqrt{-a^2+b^2}}\right ) \, dx,x,\sqrt{x}\right )}{a \sqrt{-a^2+b^2} d^2}\\ &=\frac{x^3}{3 a}+\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}-\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}+\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}-\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{40 i b x^{3/2} \text{Li}_3\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{40 i b x^{3/2} \text{Li}_3\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{(120 i b) \operatorname{Subst}\left (\int x^2 \text{Li}_3\left (-\frac{2 a e^{i (c+d x)}}{2 b-2 \sqrt{-a^2+b^2}}\right ) \, dx,x,\sqrt{x}\right )}{a \sqrt{-a^2+b^2} d^3}+\frac{(120 i b) \operatorname{Subst}\left (\int x^2 \text{Li}_3\left (-\frac{2 a e^{i (c+d x)}}{2 b+2 \sqrt{-a^2+b^2}}\right ) \, dx,x,\sqrt{x}\right )}{a \sqrt{-a^2+b^2} d^3}\\ &=\frac{x^3}{3 a}+\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}-\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}+\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}-\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{40 i b x^{3/2} \text{Li}_3\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{40 i b x^{3/2} \text{Li}_3\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{120 b x \text{Li}_4\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^4}+\frac{120 b x \text{Li}_4\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^4}+\frac{(240 b) \operatorname{Subst}\left (\int x \text{Li}_4\left (-\frac{2 a e^{i (c+d x)}}{2 b-2 \sqrt{-a^2+b^2}}\right ) \, dx,x,\sqrt{x}\right )}{a \sqrt{-a^2+b^2} d^4}-\frac{(240 b) \operatorname{Subst}\left (\int x \text{Li}_4\left (-\frac{2 a e^{i (c+d x)}}{2 b+2 \sqrt{-a^2+b^2}}\right ) \, dx,x,\sqrt{x}\right )}{a \sqrt{-a^2+b^2} d^4}\\ &=\frac{x^3}{3 a}+\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}-\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}+\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}-\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{40 i b x^{3/2} \text{Li}_3\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{40 i b x^{3/2} \text{Li}_3\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{120 b x \text{Li}_4\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^4}+\frac{120 b x \text{Li}_4\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^4}-\frac{240 i b \sqrt{x} \text{Li}_5\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^5}+\frac{240 i b \sqrt{x} \text{Li}_5\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^5}+\frac{(240 i b) \operatorname{Subst}\left (\int \text{Li}_5\left (-\frac{2 a e^{i (c+d x)}}{2 b-2 \sqrt{-a^2+b^2}}\right ) \, dx,x,\sqrt{x}\right )}{a \sqrt{-a^2+b^2} d^5}-\frac{(240 i b) \operatorname{Subst}\left (\int \text{Li}_5\left (-\frac{2 a e^{i (c+d x)}}{2 b+2 \sqrt{-a^2+b^2}}\right ) \, dx,x,\sqrt{x}\right )}{a \sqrt{-a^2+b^2} d^5}\\ &=\frac{x^3}{3 a}+\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}-\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}+\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}-\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{40 i b x^{3/2} \text{Li}_3\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{40 i b x^{3/2} \text{Li}_3\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{120 b x \text{Li}_4\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^4}+\frac{120 b x \text{Li}_4\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^4}-\frac{240 i b \sqrt{x} \text{Li}_5\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^5}+\frac{240 i b \sqrt{x} \text{Li}_5\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^5}+\frac{(240 b) \operatorname{Subst}\left (\int \frac{\text{Li}_5\left (\frac{a x}{-b+\sqrt{-a^2+b^2}}\right )}{x} \, dx,x,e^{i \left (c+d \sqrt{x}\right )}\right )}{a \sqrt{-a^2+b^2} d^6}-\frac{(240 b) \operatorname{Subst}\left (\int \frac{\text{Li}_5\left (-\frac{a x}{b+\sqrt{-a^2+b^2}}\right )}{x} \, dx,x,e^{i \left (c+d \sqrt{x}\right )}\right )}{a \sqrt{-a^2+b^2} d^6}\\ &=\frac{x^3}{3 a}+\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}-\frac{2 i b x^{5/2} \log \left (1+\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d}+\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}-\frac{10 b x^2 \text{Li}_2\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{40 i b x^{3/2} \text{Li}_3\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{40 i b x^{3/2} \text{Li}_3\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{120 b x \text{Li}_4\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^4}+\frac{120 b x \text{Li}_4\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^4}-\frac{240 i b \sqrt{x} \text{Li}_5\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^5}+\frac{240 i b \sqrt{x} \text{Li}_5\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^5}+\frac{240 b \text{Li}_6\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^6}-\frac{240 b \text{Li}_6\left (-\frac{a e^{i \left (c+d \sqrt{x}\right )}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^6}\\ \end{align*}
Mathematica [A] time = 2.04233, size = 858, normalized size = 1.1 \[ \frac{\left (b+a \cos \left (c+d \sqrt{x}\right )\right ) \left (x^3+\frac{6 b e^{i c} \left (5 x^2 \text{PolyLog}\left (2,-\frac{a e^{i \left (2 c+d \sqrt{x}\right )}}{b e^{i c}-\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right ) d^4-5 x^2 \text{PolyLog}\left (2,-\frac{a e^{i \left (2 c+d \sqrt{x}\right )}}{e^{i c} b+\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right ) d^4+i \left (x^{5/2} \log \left (\frac{e^{i \left (2 c+d \sqrt{x}\right )} a}{b e^{i c}-\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}+1\right ) d^5-x^{5/2} \log \left (\frac{e^{i \left (2 c+d \sqrt{x}\right )} a}{e^{i c} b+\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}+1\right ) d^5+20 x^{3/2} \text{PolyLog}\left (3,-\frac{a e^{i \left (2 c+d \sqrt{x}\right )}}{b e^{i c}-\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right ) d^3-20 x^{3/2} \text{PolyLog}\left (3,-\frac{a e^{i \left (2 c+d \sqrt{x}\right )}}{e^{i c} b+\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right ) d^3+60 i x \text{PolyLog}\left (4,-\frac{a e^{i \left (2 c+d \sqrt{x}\right )}}{b e^{i c}-\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right ) d^2-60 i x \text{PolyLog}\left (4,-\frac{a e^{i \left (2 c+d \sqrt{x}\right )}}{e^{i c} b+\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right ) d^2-120 \sqrt{x} \text{PolyLog}\left (5,-\frac{a e^{i \left (2 c+d \sqrt{x}\right )}}{b e^{i c}-\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right ) d+120 \sqrt{x} \text{PolyLog}\left (5,-\frac{a e^{i \left (2 c+d \sqrt{x}\right )}}{e^{i c} b+\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right ) d-120 i \text{PolyLog}\left (6,-\frac{a e^{i \left (2 c+d \sqrt{x}\right )}}{b e^{i c}-\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right )+120 i \text{PolyLog}\left (6,-\frac{a e^{i \left (2 c+d \sqrt{x}\right )}}{e^{i c} b+\sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right )\right )\right )}{d^6 \sqrt{\left (b^2-a^2\right ) e^{2 i c}}}\right ) \sec \left (c+d \sqrt{x}\right )}{3 a \left (a+b \sec \left (c+d \sqrt{x}\right )\right )} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.091, size = 0, normalized size = 0. \begin{align*} \int{{x}^{2} \left ( a+b\sec \left ( c+d\sqrt{x} \right ) \right ) ^{-1}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{x^{2}}{b \sec \left (d \sqrt{x} + c\right ) + a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{a + b \sec{\left (c + d \sqrt{x} \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{b \sec \left (d \sqrt{x} + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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